Indian wrestler Reetika Hooda displayed power and skill in equal measure while outclassing Bernadett Nagy of Hungary to enter the quarter-final of the women's 76 kg freestyle event at the Paris Olympics 2024 on Saturday. (Medal Table | Schedule & Results | Full Coverage)
India At Paris Olympics 2024: Wrestler Reetika Hooda Defeats Bernadett Nagy, Enters Quarter-Final
The referee stopped the contest with 29 seconds left in the second round as Reetika gained a 10-point lead with the final score reading 12-2 in favour of the Indian
India's Reetika Hooda and Hungary's Bernadett Nagy, in blue, compete in the round of 16 of the women's freestyle 76kg wrestling match, at Champ-de-Mars Arena. Photo: AP/Eugene Hoshiko
India's Reetika Hooda and Hungary's Bernadett Nagy, in blue, compete in the round of 16 of the women's freestyle 76kg wrestling match, at Champ-de-Mars Arena. Photo: AP/Eugene Hoshiko
The referee stopped the contest with 29 seconds left in the second round as Reetika gained a 10-point lead with the final score reading 12-2 in favour of the Indian.
The burly Reetika gained upper-hand with 4-0 lead in the first round after getting an early leg-hold followed by a flip.
The Hungarian did get a couple of points but the Indian was unstoppable in the second round with a series of two pointers. She will face top-seed Aiperi Medet Kyzy of Kyrgyzstan in the quarterfinal later today.
- Previous Story
Global Chess League 2024, Day 1 Report: Viswanathan Anand, Magnus Carlsen Draw Opening Day's Top Duel - Next StoryMary Kom Wades Into Vinesh Phogat's Weight Management Debate: 'Can't Blame Anyone'
